vector<string> Solution::reorderLogs(vector<string> &A)
{
    vector<string>res;
    set<pair<string,int>>s;
    vector<int>dig;
    int n = A.size();
    int j =0;
    for(auto x:A)
    {
        string str = "";
        int i =0;
        while(x[i]!='-')
        {
            str.push_back(x[i]);
            i++;
        }
        if(x[i+1]>='a' && x[i+1]<='z')
        {
            s.insert({x.substr(i+1)+str,j});
        }
        else
        {
            dig.push_back(j);
        }
        j++;
    }
    for(auto x:s)
    res.push_back(A[x.second]);
    for(auto x:dig)
    res.push_back(A[x]);
    return res;
}